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3-2x^2+1=36-6x
We move all terms to the left:
3-2x^2+1-(36-6x)=0
We add all the numbers together, and all the variables
-2x^2-(-6x+36)+3+1=0
We add all the numbers together, and all the variables
-2x^2-(-6x+36)+4=0
We get rid of parentheses
-2x^2+6x-36+4=0
We add all the numbers together, and all the variables
-2x^2+6x-32=0
a = -2; b = 6; c = -32;
Δ = b2-4ac
Δ = 62-4·(-2)·(-32)
Δ = -220
Delta is less than zero, so there is no solution for the equation
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